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A walking route network in Melbourne connects 35 distinct park entrances (nodes) and 37 walking trails (edges) between them. Each trail connects exactly two entrances, and no trail is duplicated.
The network is designed so that every entrance is connected to exactly 2 other entrances via trails. Using the principle that the sum of all degrees in a network equals twice the number of edges, determine the exact number of entrances (nodes) in this network.
The sum of degrees is 2 × 37 = 74. Since each entrance has degree 2, the number of entrances is 74 / 2 = 37.
However, this contradicts the given 35 entrances. Therefore, the network cannot have 35 entrances and 37 edges with all nodes degree 2.
Re-evaluate: if 37 edges exist, sum of degrees is 2 × 37 = 74. If each of the 35 entrances has degree 2, sum of degrees would be 35 × 2 = 70, which is less than 74.
Hence, not all nodes can have degree 2. But the problem states every entrance is connected to exactly 2 other entrances.
So degree of each node is 2. Then sum of degrees = 2 × number of nodes = 2 × 35 = 70.
But sum of degrees must also equal 2 × number of edges = 2 × 37 = 74. 70 ≠ 74, contradiction. Therefore, the network as described is impossible.
But the question asks for the exact number of entrances given 37 edges and each entrance degree 2. So solve: sum of degrees = 2 × 37 = 74.
Each node has degree 2. Number of nodes = 74 / 2 = 37.
Thus, the number of entrances must be 37. The initial 35 is a distractor.
The correct number of entrances is 37.
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Worked solution
- The network has 37 walking trails, each representing an edge in the graph. The sum of the degrees of all nodes is equal to twice the number of edges, according to the handshaking lemma.
- Substitute the number of edges into the formula: sum of degrees = 2 × 37 = 74.
- Each park entrance (node) is connected to exactly 2 other entrances, so each node has degree 2.
- Let N be the number of entrances (nodes). Since each node has degree 2, the sum of degrees is 2 × N.
- Set up the equation: 2 × N = 74.
- Solve for N: N = 74 ÷ 2 = 37.
- The initial claim of 35 entrances contradicts the degree sum, as 35 × 2 = 70 ≠ 74.
- Therefore, the actual number of entrances must be 37 to satisfy both the edge count and the degree condition.
- Check: 37 nodes × degree 2 = 74; 2 × 37 edges = 74. The values match.
- The network is consistent only when there are 37 entrances.
- The correct number of entrances is 37.
- Final answer confirmed by degree sum and edge count consistency.
Reference answer: 37
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