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A person walks from their home in Sydney to a park, taking two different routes. Route A goes 58 metres east and then 61 metres north.
Route B goes directly from home to the park in a straight line. What is the exact length of Route B in metres?
Use Pythagoras’ theorem and give your answer as a single exact value using a radical or integer.
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Explanation
Worked solution and answer (click to reveal)
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Worked solution
- The person walks 58 metres east and 61 metres north, forming a right-angled triangle with Route A as the two legs and Route B as the hypotenuse.
- Pythagoras’ theorem applies because the path forms a right-angled triangle, where the square of the hypotenuse equals the sum of the squares of the other two sides.
- Let a = 58 m (eastward leg), b = 61 m (northward leg), and c = ? (hypotenuse, Route B).
- Apply Pythagoras’ theorem: c² = a² + b².
- Substitute values: c² = 58² + 61².
- Calculate 58²: 58 × 58 = 3364.
- Calculate 61²: 61 × 61 = 3721.
- Add: 3364 + 3721 = 7085.
- Take the square root: c = √7085.
- Check if 7085 can be simplified: factor 7085. 7085 ÷ 5 = 1417. 1417 ÷ 13 = 109. So 7085 = 5 × 13 × 109. No repeated prime factors, so √7085 cannot be simplified further.
- Therefore, the exact length of Route B is √7085 metres.
- The answer is the exact value, as required, and matches the form of a single radical.
Reference answer: sqrt(7085)
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