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In a sports equipment allocation at a school in Melbourne, 24 rugby players are selected for a training program, and 54 students are selected for a fitness assessment. Of the 24 rugby players, 18 also participate in the fitness assessment.
If a student is selected at random from those in the fitness assessment, what is the probability that they are also a rugby player? Express your answer as an exact fraction.
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Worked solution and answer (click to reveal)
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Worked solution
- Identify the total number of students in the fitness assessment: 54.
- Identify the number of students who are both rugby players and in the fitness assessment: 18.
- The probability that a randomly selected student from the fitness assessment is also a rugby player is the ratio of rugby players in the fitness assessment to the total number in the fitness assessment.
- Set up the fraction: 18 / 54.
- Simplify the fraction by dividing both numerator and denominator by their greatest common divisor, which is 18.
- 18 ÷ 18 = 1, and 54 ÷ 18 = 3.
- The simplified fraction is 1/3.
- Verify the result: 1/3 of 54 is 18, which matches the number of rugby players in the fitness assessment.
- The question asks for the probability that a student selected at random from the fitness assessment is also a rugby player.
- The answer is 1/3, as a fraction.
- The final answer is 1/3, which is an exact fraction.
- The solution is complete and matches the required format.
Reference answer: 1/3
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