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In a simulation of a biased spinner divided into three unequal sectors, the probability of landing on sector A is 1/3, on sector B is 1/6, and on sector C is 1/2. The spinner is spun 1800 times.
What is the exact expected number of times it lands on sector C? Express your answer as a whole number or exact fraction.
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Worked solution
- The spinner has three sectors: A, B, and C. The probability of landing on sector C is given as 1/2.
- The spinner is spun 1800 times. This is the number of trials in the simulation.
- To find the expected number of times the spinner lands on sector C, multiply the probability of landing on C by the total number of spins.
- The formula for expected value is: expected number = probability × number of trials.
- Substitute the values: expected number = (1/2) × 1800.
- Perform the multiplication: (1/2) × 1800 = 1800 ÷ 2.
- Divide 1800 by 2: 1800 ÷ 2 = 900.
- The result is a whole number, so no further simplification is needed.
- The expected number of times the spinner lands on sector C is 900.
- Check: 1/2 of 1800 is 900, which matches the calculation.
- The law of large numbers suggests that with 1800 trials, the observed frequency should be close to the expected value of 900.
- The final answer is 900, as the expected number of times sector C is landed on.
Reference answer: 900
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