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A walking route in Melbourne offers two independent choices at a junction: a path to the lake (L) or a path to the forest (F), and a choice of direction at the next fork: left (X) or right (Y). The probability of choosing the lake path is 62/100, and the probability of choosing the left direction at the second fork is 58/100.
Using a two-way table to represent all possible combinations of the two events, determine the exact probability that a walker chooses the lake path AND the left direction. Express your answer as a simplified fraction.
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Worked solution
- The two independent events are: choosing the lake path (L) with probability 62/100, and choosing the left direction (X) at the second fork with probability 58/100.
- Since the two choices are independent, the probability of both occurring together is the product of their individual probabilities.
- Set up the multiplication: Pr(L and X) = Pr(L) × Pr(X) = (62/100) × (58/100).
- Multiply the numerators: 62 × 58 = 3596.
- Multiply the denominators: 100 × 100 = 10000.
- The combined probability is 3596/10000.
- Simplify the fraction by finding the greatest common divisor (GCD) of 3596 and 10000. First, factor both numbers.
- Factor 3596: divide by 2 → 1798, again → 899. 899 ÷ 29 = 31. So 3596 = 2² × 29 × 31.
- Factor 10000: 10000 = 10⁴ = (2×5)⁴ = 2⁴ × 5⁴.
- The common factors are 2² = 4. Divide numerator and denominator by 4: 3596 ÷ 4 = 899, 10000 ÷ 4 = 2500.
- The simplified fraction is 899/2500. Check that 899 and 2500 have no common factors: 899 = 29×31, 2500 = 2²×5⁴. No common prime factors.
- Therefore, the probability that a walker chooses the lake path AND the left direction is 899/2500.
Reference answer: 899/2500
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