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A craft designer is creating a symmetrical wooden inlay using the quadratic function f(x) = x^2 - 61x + 30 to model the curved edge. The vertex of the parabola defines the highest point of the curve.
What is the exact x-coordinate of the vertex?
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Explanation
Worked solution and answer (click to reveal)
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Worked solution
- The quadratic function is given as f(x) = x^2 - 61x + 30. This is in standard form, f(x) = ax^2 + bx + c, where a = 1, b = -61, and c = 30.
- The x-coordinate of the vertex of a parabola in standard form is given by the formula x = -b/(2a). This formula is derived from completing the square and gives the axis of symmetry.
- Substitute the values of a and b into the vertex formula: x = -(-61) / (2 * 1).
- Simplify the numerator: -(-61) = 61.
- Simplify the denominator: 2 * 1 = 2.
- Divide: 61 / 2 = 30.5.
- The x-coordinate of the vertex is 30.5. This is the point where the parabola reaches its maximum or minimum. Since a = 1 > 0, the parabola opens upwards, so the vertex is a minimum point.
- The question asks for the x-coordinate of the vertex, which is 30.5. This is an exact value, not an approximation.
- Check: substitute x = 30.5 into the vertex formula to confirm: x = -(-61)/(2*1) = 61/2 = 30.5. The calculation is consistent.
- Verify using symmetry: the roots of f(x) = 0 are symmetric about x = 30.5. The sum of the roots is 61 (from -b/a), so the midpoint is 61/2 = 30.5. This confirms the vertex lies at x = 30.5.
- The vertex x-coordinate is exactly 30.5, which is the point of symmetry and the minimum of the function.
- The exact x-coordinate of the vertex is 30.5.
Reference answer: 30.5
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