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A statistical investigation was conducted in Adelaide to examine the effect of a new teaching method on student performance in a Year 7 mathematics test. The test scores (out of 100) for 12 students who used the new method were: 78, 82, 76, 80, 84, 79, 81, 83, 77, 82, 80, 85.
Calculate the exact mean score. Express your answer as a simplified fraction.
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Worked solution
- The given data consists of 12 test scores: 78, 82, 76, 80, 84, 79, 81, 83, 77, 82, 80, 85. These are discrete numerical values representing student performance out of 100.
- To find the mean, sum all the scores and divide by the number of students, which is 12.
- Add the scores step by step: 78 + 82 = 160; 160 + 76 = 236; 236 + 80 = 316; 316 + 84 = 400; 400 + 79 = 479; 479 + 81 = 560; 560 + 83 = 643; 643 + 77 = 720; 720 + 82 = 802; 802 + 80 = 882; 882 + 85 = 967.
- The total sum of the 12 scores is 967.
- Divide the sum by the number of students: 967 ÷ 12.
- Perform the division: 967 ÷ 12. 12 × 80 = 960, so 967 − 960 = 7. Therefore, 967 ÷ 12 = 80 + 7/12.
- The result is 80 and 7/12. As an improper fraction: (80 × 12 + 7) / 12 = (960 + 7) / 12 = 967/12.
- Check if 967/12 can be simplified. The greatest common divisor of 967 and 12 is 1, since 967 is a prime number (verified by testing divisibility by primes up to √967 ≈ 31.1).
- Therefore, 967/12 is already in simplest form.
- The mean score is 967/12.
- Verify by multiplying the mean by 12: (967/12) × 12 = 967, which matches the original sum.
- The exact mean score is 967/12.
Reference answer: 967/12
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