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Two friends, Alex and Jordan, are comparing walking routes from their home in Melbourne to a park. Alex takes a path that follows a quadratic distance-time relationship given by d = t^2 - 22t + 59, where d is the distance in metres from home and t is the time in seconds.
Jordan takes a different route that follows d = t^2 - 22t + 64. At what time t (in seconds) do both routes have the same distance from home?
Give your answer as an exact value.
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Worked solution and answer (click to reveal)
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Worked solution
- The problem gives two quadratic distance-time equations: d_Alex = t^2 - 22t + 59 and d_Jordan = t^2 - 22t + 64. We are to find the time t when both distances are equal.
- Set the two expressions for d equal to each other: t^2 - 22t + 59 = t^2 - 22t + 64.
- Subtract t^2 from both sides: -22t + 59 = -22t + 64.
- Add 22t to both sides: 59 = 64.
- This results in a contradiction: 59 = 64 is false. Therefore, there is no value of t for which the two expressions are equal.
- Since the two quadratic functions have identical t^2 and t coefficients but different constant terms, they are parallel parabolas shifted vertically. They never intersect.
- The absence of a solution means that the two routes never have the same distance from home at any time t.
- Therefore, there is no real value of t that satisfies the condition.
- The question asks for the time t when both routes have the same distance from home. Since no such t exists, the answer is that no solution exists.
- However, the question specifies to give an exact value. Since no value satisfies the equation, the correct response is that no such time exists.
- Rechecking: the two equations differ only in the constant term (59 vs 64). The difference is constant: (t^2 - 22t + 64) - (t^2 - 22t + 59) = 5. So d_Jordan is always 5 m greater than d_Alex. They never equal.
- Thus, there is no time t at which both routes have the same distance from home. The answer is that no such time exists.
Reference answer: No solution exists
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