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A craft designer in Brisbane records the length of wire (x in cm) used and the number of decorative beads (y) strung on each piece over 10 designs. The bivariate data collected is: (92, 61), (94, 63), (96, 65), (98, 67), (100, 69), (102, 71), (104, 73), (106, 75), (108, 77), (110, 79).
Using linear regression, determine the exact value of the y-intercept of the line of best fit for this data set. Express your answer as a simplified fraction.
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- The data consists of 10 pairs of bivariate measurements: (x, y) where x is the length of wire in cm and y is the number of beads. The values are: (92, 61), (94, 63), (96, 65), (98, 67), (100, 69), (102, 71), (104, 73), (106, 75), (108, 77), (110, 79).
- To find the y-intercept of the line of best fit using linear regression, we use the formula for the line of best fit: y = mx + b, where b is the y-intercept. The formula for b is: b = (Σy)(Σx²) - (Σx)(Σxy) / [n(Σx²) - (Σx)²].
- We compute the required sums: Σx, Σy, Σxy, Σx², and n = 10.
- Σx = 92 + 94 + 96 + 98 + 100 + 102 + 104 + 106 + 108 + 110. This is an arithmetic series with first term 92, last term 110, and 10 terms. Sum = (10/2) × (92 + 110) = 5 × 202 = 1010.
- Σy = 61 + 63 + 65 + 67 + 69 + 71 + 73 + 75 + 77 + 79. This is an arithmetic series with first term 61, last term 79, and 10 terms. Sum = (10/2) × (61 + 79) = 5 × 140 = 700.
- Σxy = (92×61) + (94×63) + (96×65) + (98×67) + (100×69) + (102×71) + (104×73) + (106×75) + (108×77) + (110×79). We compute each product: 92×61 = 5612, 94×63 = 5922, 96×65 = 6240, 98×67 = 6566, 100×69 = 6900, 102×71 = 7242, 104×73 = 7592, 106×75 = 7950, 108×77 = 8316, 110×79 = 8690. Sum = 5612 + 5922 = 11534; +6240 = 17774; +6566 = 24340; +6900 = 31240; +7242 = 38482; +7592 = 46074; +7950 = 54024; +8316 = 62340; +8690 = 71030. So Σxy = 71030.
- Σx² = 92² + 94² + 96² + 98² + 100² + 102² + 104² + 106² + 108² + 110². We compute each square: 92² = 8464, 94² = 8836, 96² = 9216, 98² = 9604, 100² = 10000, 102² = 10404, 104² = 10816, 106² = 11236, 108² = 11664, 110² = 12100. Sum = 8464 + 8836 = 17300; +9216 = 26516; +9604 = 36120; +10000 = 46120; +10404 = 56524; +10816 = 67340; +11236 = 78576; +11664 = 90240; +12100 = 102340. So Σx² = 102340.
- Now substitute into the formula for b: b = [Σy × Σx² - Σx × Σxy] / [n × Σx² - (Σx)²]. Numerator = (700 × 102340) - (1010 × 71030). Compute 700 × 102340 = 71,638,000. Compute 1010 × 71030 = 1010 × 71000 = 71,710,000; 1010 × 30 = 30,300; total = 71,740,300. So numerator = 71,638,000 - 71,740,300 = -102,300.
- Denominator = 10 × 102340 - (1010)² = 1,023,400 - 1,020,100 = 3,300.
- So b = -102,300 / 3,300. Simplify the fraction: divide numerator and denominator by 100: -1023 / 33. Now divide 1023 by 33: 33 × 31 = 1023. So -1023 / 33 = -31. Therefore, b = -31.
- The y-intercept of the line of best fit is -31. This means that if no wire were used (x = 0), the model predicts -31 beads, which is not physically meaningful but mathematically valid for the regression line.
- The result is verified by noting that the data shows a perfect linear pattern: for every 2 cm increase in wire length, the number of beads increases by 2. The slope is 1. Using point (100, 69), the equation is y = x - 31. So when x = 0, y = -31. This confirms the y-intercept is exactly -31.
Reference answer: -31
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