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In a community garden in Melbourne, a rectangular plot is divided into 44 equal-sized sections for growing vegetables. Each section is assigned a unique number from 1 to 44.
A resident randomly selects one section to plant lettuce. What is the exact probability that the selected section number is a multiple of 4 or 6?
Express your answer as a simplified fraction. (Hint: Use inclusion-exclusion principle to count the number of favourable outcomes.)
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Worked solution
- The total number of sections is 44, each uniquely numbered from 1 to 44. This is the sample space, so the total number of possible outcomes is 44.
- We need to find the number of sections where the number is a multiple of 4 or 6. This is a union of two sets: multiples of 4 and multiples of 6.
- Use the inclusion-exclusion principle: |A ∪ B| = |A| + |B| - |A ∩ B|, where A is multiples of 4, B is multiples of 6.
- Count the multiples of 4 from 1 to 44: 4, 8, 12, ..., 44. This is an arithmetic sequence with first term 4, last term 44, common difference 4. Number of terms = (44 - 4)/4 + 1 = 40/4 + 1 = 10 + 1 = 11.
- Count the multiples of 6 from 1 to 44: 6, 12, 18, ..., 42. First term 6, last term 42, common difference 6. Number of terms = (42 - 6)/6 + 1 = 36/6 + 1 = 6 + 1 = 7.
- Find the common multiples of 4 and 6, i.e., multiples of their LCM. LCM(4,6) = 12. So count multiples of 12: 12, 24, 36. First term 12, last term 36, common difference 12. Number of terms = (36 - 12)/12 + 1 = 24/12 + 1 = 2 + 1 = 3.
- Apply inclusion-exclusion: number of favourable outcomes = 11 (multiples of 4) + 7 (multiples of 6) - 3 (common multiples) = 15.
- The probability is the number of favourable outcomes divided by total outcomes: 15 / 44.
- Check if 15/44 can be simplified. GCD of 15 and 44 is 1, so the fraction is already in simplest form.
- The probability that the selected section number is a multiple of 4 or 6 is 15/44.
- Verify by listing: multiples of 4: 4,8,12,16,20,24,28,32,36,40,44 (11 numbers). Multiples of 6: 6,12,18,24,30,36,42 (7 numbers). Common: 12,24,36 (3 numbers). Union: 11 + 7 - 3 = 15. Correct.
- Final answer: 15/44.
Reference answer: 15/44
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