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Two friends start walking from the same point in Brisbane. Alice walks 74 metres east and then 61 metres north.
Ben walks 61 metres east and then 74 metres north. Using the Pythagorean theorem and algebraic simplification, find the exact difference in the straight-line distances they each travel from the starting point.
Express your answer as a simplified radical expression.
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Worked solution
- Alice walks 74 m east and 61 m north, so her straight-line distance from the start is the hypotenuse of a right triangle with legs 74 m and 61 m.
- Ben walks 61 m east and 74 m north, so his straight-line distance is the hypotenuse of a right triangle with legs 61 m and 74 m.
- The Pythagorean theorem states that for a right triangle with legs a and b, and hypotenuse c, c^2 = a^2 + b^2.
- For Alice: d_A^2 = 74^2 + 61^2 = 5476 + 3721 = 9197.
- For Ben: d_B^2 = 61^2 + 74^2 = 3721 + 5476 = 9197.
- Both d_A^2 and d_B^2 equal 9197, so d_A = sqrt(9197) and d_B = sqrt(9197).
- The difference in straight-line distances is d_A - d_B = sqrt(9197) - sqrt(9197) = 0.
- Since both paths result in the same hypotenuse length, the difference is exactly zero.
- No simplification of a radical is needed because the difference is zero.
- The algebraic expression for the difference is sqrt(74^2 + 61^2) - sqrt(61^2 + 74^2), which simplifies to 0.
- The symmetry in the legs (74 and 61) means the hypotenuse is identical regardless of order.
- Therefore, the exact difference in straight-line distances is 0 metres.
Reference answer: 0 m
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